x = e^((4+3i)x)
y = 12e^((-5+4i)x)
What is xy?
Can anyone solve is step by step?
i = imaginary number ^_^
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x = e^((4+3i)x)
y = 12e^((-5+4i)x)
What is xy?
Can anyone solve is step by step?
i = imaginary number ^_^
-repeat-
one question, x isn't a whole # or a real #, right? if yes, then I'm not gonna bother to do it, I have no clue.
edit: it can't be, I can't think of a way to cancel out the i. dude, you're making this too difficult, ...no...maybe I'm just no smart enough to figure this out. x.x
lol, its not an easy one...
-repeat-
This isn't that hard. The answer is xy = jjasdkfjljvviruskjhvisrus.jkdlfuckjfdsljdf
An eye for an eye brings justice, but it is compassion that changes a man.
Another point of view doesn't necessarily make yours more or less right.
xy =
12e^[((4+3i)x) + ((-5+4i)x)]
12e^[x(4+3i-5+4i)]
12e^[x(-1+7i)]
*blank* Tell me if I'm right?
Is the answer further than this? ~_~
- same person; no difference at all, just a different sex
^ can you leave a X on the left side of the equation???
I thought xy has to equal certain #... if not, then is xy = 12e^[2x^2(-32+i)]??
v that's because I thought you can
Err, you've still got an x on both sides though... ~_~
And I don't know... I can't get rid of the e^x...
<edit> Well, err, I assumed it's not right to still have the x... Which is why I said "I can't get rid of the e^x"
Err, how did you get 2x? When you multiply e's, you *add* the indices...
- same person; no difference at all, just a different sex
^ try natural logs...I think ^_^'
Quote by j0n0This isn't that hard. The answer is xy = jjasdkfjljvviruskjhvisrus.jkdlfuckjfdsljdf
LOOOOOOOOOOOOOL
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hey jasaiyajin, my calculator told me the answer to xy is 9.974058285E-11-1.335133474E-10i, now will you please reveal the steps now??! lol
okay, here's my third/forth whatever try (after tevi's)
xy= 12e^[(4X+3Xi)+(-5X+4Xi)
xy= 12e^(-X+7Xi)
xy= 12e^ (-25+175i)
xy= 9.974058285E-11-1.335133474E-10i
tevi: "Err, how did you get 2x? When you multiply e's, you *add* the indices..."
lol, yeah, I wasn't thinking, I forgot how to do these. I had to set myself an example in order to think that's the way
to do it, lol oh lord....
tavi got it... lol
-repeat-
except...x is on both sides...making it incorrect...or is it just fine for here?
no taffystar, you still can define a variable that is dependant on itself. These kind of equations or typically called differeantial equations or trancendental equations (two are not the same). The operations that were done to get xy aren't illigal in math, it was just basic algebra manipulations. The only thing happens was the x = e^((4+3i)x),- a trancendental equation- made the xy also a trancendental equation.
An eye for an eye brings justice, but it is compassion that changes a man.
Another point of view doesn't necessarily make yours more or less right.
meh, my teacher always told us to get all the x's on one side, even with differential functions and definitely with transcendental functions. Maybe not incorrect, persay, maybe...incomplete
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