Quote by EternalEthelionthis may not be a trick question but a brain
twister, actually no matter what you call it, you still have to think.. think about it! hehe.. :P
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Quote by rituelthis is similar
to my 30 dollars question.. what i remember is it's a mathematical error.. for some reason you can't do the
math that way.. XD
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Simple bookkeeping... The way in which this the 'riddle' is written is fallacious
Credits
t=0 -------------- t=1 --------- t=2 --------- t=3 --------- t=4
50 (50) --------- (100) -------- (3) ------- 97 (100) ------ (98)
50 (100)
Debits
t=0 -------------- t=1 --------- t=2 --------- t=3 --------- t=4
50 (50) ------- 97 (197) ----- (100) ------- (100) ------ 2x1 (98)
50 (100)
t=0 time of loan (instantaneously obtain credit and debit, unlike t=1,2,3)
t=1 time when you pick controller off shelf (literally, before you pay at the counter, your debits are now loan 1 + loan
2 + controller $197) [you credits are still $100]
t=2 when you pay for the controller [(D) = 100; (C) = 3] *note shopkeeper now has controller and your money
t=3 when you are given the controller by the shopkeeper [(D) = 100; (C) = 100]
t=4 when you repay the one dollar to the two friends [(D) = 98; (C) = 98]
Notice how credits and debits balance at the end of it all? The trick comes in with the dollar you get at the end of it,
it is both a debit and a credit; you got it back as change (and didnt repay it for whatever reason $0.50c is reasonable
to repay?), but it is not technically yours. Another thing was to discount the controller as a credit... although not
money, if you give the controller and one dollar to both friends at t=4 then you repay the loans.
^^ boy that wasnt "simple" I hope I got it right :)
